How to skip the parent tag, based on the value of a child tag in XML Parsing using SAX Parser

Question

<root>
<parent>
    <child1> 30</child1>
    <child2> 30</child2>
    <child3> 30</child3>
</parent>
 <parent>
    <child1> 20</child1>
    <child2> 30</child2>
    <child3> 30</child3>
</parent>
 <parent>
    <child1> 30</child1>
    <child2> 30</child2>
    <child3> 30</child3>
</parent>
</root>

I am really new to the world of coding and to sax parsing.. Consider the above XML, what I need is. .. based on the value of the tag child1, if it is greater than 20, only then I would want to parse the remaining child tags(child2 and child3), otherwise I would want to move on to the next parent tag.

Could anyone pls suggest what would be the ideal way to do it?

Yes it is for huge xml , and also it is an already existing code, I am trying to do some modifications. — Vipul Reddy, Apr 29 '16 at 05:43
Not 'GB' huge. It is less than a hundered MB. Do you suggest any other parser instead of SAX in such a case, which would help me with the above situation? — Vipul Reddy, Apr 29 '16 at 06:40

score 1 · Accepted Answer · answered Apr 29 '16 at 05:22

Something like that:

...
private boolean skipChildren;
private StringBuilder buf = new StringBuilder();
...

@Override
public void startElement(String uri, String localName, String qName,
        Attributes attributes) throws SAXException {
    if (qName.equals("parent")) {
        skipChildren = false;
        ...
    } else if (qName.equals("child1")) {
        buf.setLength(0);
        ...
    } else if (qName.startsWith("child")) {
        if (!skipChildren) {
            buf.setLength(0);
            ...
        }
    }
}

@Override
public void endElement(String uri, String localName, String qName)
        throws SAXException {
    if (qName.equals("parent")) {
        ...
    } else if (qName.equals("child1")) {
        int value = Integer.parseInt(buf.toString().trim());
        if (value <= 20) {
            skipChildren = true;
        }
        ...
    } else if (qName.startsWith("child")) {
        if (!skipChildren) {
            int value = Integer.parseInt(buf.toString().trim());
            doSomethingWith(value);
        }
    }
}

@Override
public void characters(char[] ch, int start, int length) {
    if (!skipChildren) {
        buf.append(ch, start, length);
    }
}

so many thanks for your reply but shouldn't it be if(skipChildren) in startElement function? @Maurice Perry — Reza Namvar, Jan 31 '22 at 16:35
@RezaNamvar no: you want to skip the children if `skipChildren` is true, not process them. — Maurice Perry, Jan 31 '22 at 20:57

vtd-xml-author · Answer 2 · 2016-05-04T22:19:52.167

Below is the code to perform your task with vtd-xml, it is the state of art in xml processing technology, and is a lot more efficient and simpler to write than SAX... the key is by using xpath expression to filter out only the nodes of interest... read this paper that gives you loads of reasons to avoid SAX parsing whenever possible

Processing XML with Java – A Performance Benchmark

import com.ximpleware.*;
public class conditionalSelection {
    public static void main(String s[]) throws VTDException{
        VTDGen vg = new VTDGen();
        if(!vg.parseFile("d:\\xml\\condition.xml", false)) // disable namespace
            return;
        VTDNav vn = vg.getNav();
        AutoPilot ap = new AutoPilot(vn);
        ap.selectXPath("/root/parent[child1>20]"); // the xpath selecting all parents with child1>20
        int i=0,j=0;
        while((i=ap.evalXPath())!=-1){
            // now move the cursor to child2 and child3
            if(vn.toElement(VTDNav.FC,"child2")){
                j = vn.getText();
                if (j!=-1)//make sure the text node exist
                    System.out.println(" child2's text node is ==>"+ vn.toString(j));
                vn.toElement(VTDNav.P);
            }
            if(vn.toElement(VTDNav.FC,"child3")){
                j = vn.getText();
                if (j!=-1)//make sure the text node exist
                    System.out.println(" child3's text node is ==>"+ vn.toString(j));
                vn.toElement(VTDNav.P);
            }
        }
    }

How to skip the parent tag, based on the value of a child tag in XML Parsing using SAX Parser

2 Answers2