I have one byte that contains Upper 4 bits are a bitmap for system status like 0x40,0x80 and Lower 4 bits values like 0,1,2,3. I do not know to parse them.Can someone help me.can I have anything like this?how byte will look like???will it be byte b=(byte)0x80?
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What exactly are you trying to achieve? And what have you tried so far? – Mureinik Jan 18 '16 at 09:19
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lets say I have byte b=01000000 I need for upper 4 bits value only 0x40(64 in decimal) and for lower bits my value must be evaluated to 0. – Priya Kothari Jan 18 '16 at 09:25
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Bit masking. To get the upper 4 bits:
Upper=byte&0xF0
To get the first
First=byte&0x01
And so on.
ddacot
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byte b=(byte)00100010; int Upper= b & 0xF0; int First= b & 0x01; System.out.println(Integer.toBinaryString(First));It bring 0 as output for Upper . – Priya Kothari Jan 18 '16 at 09:30