No. Your DFA is equivalent to the expression (0*1+)+
The expression that you've specified requires at least three 1
to be accepted. Breaking it down into parts
0*
1*
1+ <-- Required at least once
1 <-- Required
1*
0*
1 <-- Required
A DFA that is equivalent to your expression needs to represent this looks like this:

Image created with the Regex visualizer, which allows you to generate these graphs from regular expressions.
Update: If +
means or, this changes things. Your original DFA is still not equivalent. You're missing that if the accepted string starts with a 1
it will need to be followed by at least one more 1
to be accepted. The DFA for the expression looks like this:

As generated by inputting 0*1*1|11*0*1
into the visualizer.