Python: try/except OSerror errno 2

Question

I'm writing a script where the user selects a directory and hits ok.

That I've sussed pretty easily, but I'm trying to sort error handling side, but it's not going to plan.

Essentially, I want to continue the script unless OSError Errno 2 is called.

at the moment, I have: import IOError ... ...

if ok==1:
  try:
    folder = selection
    myFunction(folder)
  except IOError:
    print "Select a folder, not a file"

I've tried using except without IOError, but that causes problems elsewhere in the script (In a different function completely)

Anyone have a suggestions?

Thanks

Have you tried to except `OSError`? – sobolevn Sep 12 '15 at 07:43 — sobolevn, Sep 12 '15 at 07:43

mid · Answer 1 · 2015-09-12T07:39:43.513

1

I don't know what you mean by OSError Errno 2, but what ever error you want you can handle in if and ignore all the others with pass statement

try:
    folder = selection
    myFunction(folder)
except Exception as e:
    if "I/O operation failed" in e.__doc__:
        print "bingo"
    else:
        pass

edited Sep 12 '15 at 07:39

answered Sep 12 '15 at 07:32

mid

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Thanks, guys. Much appreciated – James Porter Sep 13 '15 at 02:29

score 0 · Accepted Answer · answered Sep 12 '15 at 07:33

0

Use os.path.isdir(folder)

Python - isdir

answered Sep 12 '15 at 07:33

Conans

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score 0 · Answer 3 · answered May 26 '16 at 22:06

0

Another way and more explicit would be:

try:
    os.remove(filepath)
except OSError, e:
    print e

However, depending on the frequency the Exception is called this method can impact speed.

answered May 26 '16 at 22:06

user1767754

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Python: try/except OSerror errno 2

3 Answers3