Groovy each immutability

Asked Sep 08 '15 at 17:19

Active Sep 08 '15 at 21:43

Viewed 91 times

From the following code snippet I tried, This runs into an infinite loop regardless of the fact that I mark the initial ds as immutable, and looping it with an each. What am I missing? -

domObject.Whatever.'**'.findAll { it.name() == 'Node' }.asImmutable().each { node -> //Bazinga
    nodes.split(/(;|,|\n|&)/).eachWithIndex { nodeName, index ->
        def newNode = new Node(null, node.name(), node.attributes(), node.value())
        newNode.@name = nodeName
        //I'm simply adding new nodes here
        node.parent().children().add(0, newNode)     //bazinga
    }
}

Ive used an xmlparser for the domObject.

edited Sep 08 '15 at 21:43

August Lilleaas

54,010
13
102
111

asked Sep 08 '15 at 17:19

dexter31

1

`asImmutable()` returns an immutable copy of the collection. It does not make the original collection immutable. – cjstehno Sep 08 '15 at 18:04
in which case there must be no infinite loops - is that right/ – dexter31 Sep 08 '15 at 18:17
3

where does 'nodes' in the inner closure come from? – PhilBa Sep 08 '15 at 18:44

Groovy each immutability

0 Answers0