Round does not accept argument type(Int)

Question

I'm trying to create my app about a math test as I come to division. I know that I can't create repeating infinite decimals, and I must keep the numbers random. So after I generated the numbers out of arc4random_uniform, I'm trying to use the round function. But it said

Cannot find an overload for round that accepts argument type (Int)

How do I fix this?

Here's my code:

 var randomNumber:UInt32 = arc4random_uniform(999)
 var randomNumber2:UInt32 = arc4random_uniform(999)
 // 1000 is my maximum number for now.
 randomNumber += 1
 randomNumber2 += 1
 if operation.text == "/" {
     if randomNumber < randomNumber2 {
         var between:UInt32 = 1000 - randomNumber2
         randomNumber = randomNumber2 + arc4random_uniform(between - 1)
         // making sure that randomNumber is not smaller than randomNumber2,
         // therefore all results are positive.
     }
     var answer:Int = round(Int(randomNumber)/Int(randomNumber2))
 }

score 0 · Accepted Answer · answered Jul 14 '15 at 10:08

0

You have to pass a Float value to round since it doesn't have prototypes using Int value:

var answer = round(Float(randomNumber)/Float(randomNumber2))

answered Jul 14 '15 at 10:08

tbaranes

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Will the result end up being an integer or a float? – Justsoft Jul 15 '15 at 01:48
It will be return a Float – tbaranes Jul 15 '15 at 06:25
Could I make it an int or at least leave only one decimal place? – Justsoft Jul 16 '15 at 03:58
It's up to you, depending of which precision do you need. Your value will be more precise if you keep it as a Float. – tbaranes Jul 16 '15 at 06:24
How do I make it an int? – Justsoft Jul 18 '15 at 01:37
`var answer: Int = round(Float(randomNumber)/Float(randomNumber2))` – tbaranes Jul 18 '15 at 08:15
That brings up the same problem – Justsoft Jul 20 '15 at 06:30

Round does not accept argument type(Int)

1 Answers1