Instantiating multiple mutable variable

Question

I have instantiated multiple mutable variable:

SimpleStringBuffer a=new SimpleStringBuffer();
SimpleStringBuffer b=new SimpleStringBuffer();

I have done this 11 times, I know there is some way to avoid doing it using array or collections but I am not sure how. Can anyone help me with this?

You should add a tag for the language you use. – qwerty_so May 17 '15 at 18:03 — qwerty_so, May 17 '15 at 18:03

score 1 · Accepted Answer · answered May 17 '15 at 19:05

1

You could use an array of SimpleStringBuffers:

SimpleStringBuffer arr = new SimpleStringBuffer[11];
for (int i = 0; i < arr.length; ++i) {
    arr[i] = new SimpleStringBuffer();
}

Or a List:

List<SimpleStringBuffer> list = new ArrayList<>(11);
for (int i = 0; i < 11; ++i) {
    list.add(new SimpleStringBuffer());
}

answered May 17 '15 at 19:05

Mureinik

What should be done if I want to repeat the same procedure for the Map ? – MR AND May 18 '15 at 14:05
@user4230977 What Map? Can you elaborate the question please? – Mureinik May 18 '15 at 15:33
If i instantiate map in multiple places like this Map row1=new HashMap(); Map row2=new HashMap(); Map row3=new HashMap(); Map row4=new HashMap(); Is there a similar way to avoid multiple instantiation? – MR AND May 18 '15 at 15:41
1

@user4230977 the same technique will work for that too – Mureinik May 18 '15 at 17:45

1 Answers1