I have written a function that accepts up to 4 options and 2 arguments. The options are -1, -2, -3, and -u. By default, their values are set to true, true, true, and false, respectively, but enabling any of the options causes that value to flip. Problem is, even when I specify, say,
python comm.py -1 -2 -u test test2
and print the option's values, they still show the default values. Below is the relevant portion of my code:
...
...
...
parser.add_option("-1", action="store_false", dest="xcol1", default=True, help="...")
parser.add_option("-2", action="store_false", dest="xcol2", default=True, help="...")
parser.add_option("-3", action="store_false", dest="dups", default=True, help="...")
parser.add_option("-u", action="store_true", dest="donotsort", default=False, help="...")
options, args = parser.parse_args(sys.argv[2:])
xcol1=options.xcol1
xcol2=options.xcol2
dups=options.dups
donotsort=options.donotsort
print "xcol1:"
print xcol1
print "xcol 2:"
print xcol2
print "dups:"
print dups
print "donotsort:"
print donotsort
print args
...
...
...
Executing the aformentioned command with the above code will output:
True
False
True
True
test, test2
i.e., the default values. It really should be outputting "False, False, True, True, ...), since options 1, 2, and u are enabled. What am I doing wrong? Is it something to do with the parser, because I'm not 100% sure I'm using the parser correctly.
Additionally, when I list the options as -12u
instead of -1 -2 -u
, it behaves differently - the boolean values are different