Getting error: 'shared_ptr' in namespace 'std' does not name a type

Question

I am trying to compile an android application in android studio (ndk r10d) which uses some C++ code. I needed C++11 so I added -std=gnu++11 (I need gnu++11 instead of c++11 for an extension I am using). I am using the stlport stl, due to other libraries I am using that use this stl library. So my cFlags and stl parameters in the build.gradle file looks like this:

stl "stlport_static"
cFlags " mylib1.a mylib2.a ... -fexceptions -frtti -std=gnu++11"

I also have included memory: #include <memory>

When trying to compile I receive this error:

'shared_ptr' in namespace 'std' does not name a type

I have been using the boost implementation for the smart pointers till now but with the move to c++11 I would rather use the standard implementation.

The original error is on this define I added to make code shorter but the errors are seen throughout the files wherever I try to use this macro: #define myapp_shared_ptr std::shared_ptr — royeet, Mar 07 '15 at 16:33
shared_ptr doesn't name a type. It names a type template. Are you sure you're doing shared_ptr when you use it? The error I get when I leave that out is "use of class template requires template arguments" — Charlie, Mar 08 '15 at 03:42

score 44 · Answer 1 · edited Jan 16 '20 at 19:45

44

http://en.cppreference.com/w/cpp/memory/shared_ptr/make_shared use head file in your code.

#include <memory>

edited Jan 16 '20 at 19:45

CantrianBear

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answered Dec 03 '15 at 08:52

MYLOGOS

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Is this necessary? – IgorGanapolsky Jun 24 '16 at 15:32
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I had this same problem and shared_ptr is not defined in when using stlport_static. This answer is pointless. – juzzlin Aug 23 '16 at 08:42
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#include worked for me. The standard says that it is defined in – nishant Jul 31 '18 at 21:01
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For me, this was necessary with g++ on Linux, but not msvc on Windows. – g01d Apr 05 '19 at 17:53
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you don't need above, just – Goblinhack May 01 '19 at 00:27
worked for a similar error for 'auto_ptr' in namespace 'std' does not name a type – Mona Wade Jul 21 '20 at 22:08

score 2 · Accepted Answer · answered Mar 19 '15 at 09:41

@T.C Looks like you were right. I saw your claim on a different question while looking for a solution for my problem, but as libraries that I am using are compiling with C++11 and STLport I thought that this claim might not be true.

What I think happened is that the libraries I'm using are not using any C++11 features that the STLport is missing. They are only using C++11 features that the gcc compiler supports. I need the gnuStl to support the features that I am using.

My solution was to use the boost implementation for the smart pointers and all other missing C++11 features.

Yes, GNU STL supports all C++11 features. – juzzlin Aug 23 '16 at 09:00 — juzzlin, Aug 23 '16 at 09:00

score 1 · Answer 3 · answered Sep 28 '18 at 11:42

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I got here googling for a similar error, but the answer did not work:

error: ‘shared_pointer’ in namespace ‘std’ does not name a template type

In my case, it was a typo:

std::shared_pointer

should be

std::shared_ptr

answered Sep 28 '18 at 11:42

miravalls

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Getting error: 'shared_ptr' in namespace 'std' does not name a type

3 Answers3