Looping a Lua table matching for a specific key then setting the value to a variable

Question

So I have a table that looks something like this:

local weapons = {[46]= "Megapositron", [173]= "Sunflare", [702]= "raven"}

I also have a variable:

weaponid

The variable weaponid will contain one of the keys from weapons (46,173,702)

What I can't figure out is how to check if weaponid matches one of those keys and upon weapon id matching a key I need it to assign the keys value to another variable named weaponname.

So suppose weaponid = 173 then weaponname = 'Sunflare'

Wow, it was that easy? Thanks John and Jan! I spent hours trying to do this in a for loop. — moretimetocry, Jul 31 '14 at 15:01

score 2 · Accepted Answer · answered Jul 31 '14 at 14:52

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local weaponname = weapons[weaponid]

weaponname will be nil if the id doesn't match any of the keys.

answered Jul 31 '14 at 14:52

John Calsbeek

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score 0 · Answer 2 · answered Jul 31 '14 at 14:54

0

weaponname = weapons[weaponid] or weaponname

This way, the old weapon name will be kept if there is no weapon associated to the new id.

answered Jul 31 '14 at 14:54

Jan Berktold

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You'd probably want to use "Unknown Weapon" instead of the last weapon's name. – Advert Jul 31 '14 at 15:09

Looping a Lua table matching for a specific key then setting the value to a variable

2 Answers2