ILMath function to arrange values given start, end and step size?

Question

I am trying to get an array linearly spaced given the step size.

For Example

arange(10,15,0.5) = 10.5, 11, 11.5, 12, 12.5, 13, 13.5, 14, 14.5,15

arange(10, 15, 1) = 11, 12, 13, 14

There is linspace function that accepts only number of elements to be generated. Is there a way to provide step size instead of the number of elements?

For now, I calculate number of elements manually and use linspace to get the result.

Is there any straight to use api to get desired output? Thanks

is it intentional, that in your first example the upper bound is included in the output, but in the second example it is not? — elias, May 08 '14 at 12:25

score 2 · Accepted Answer · edited May 09 '14 at 14:11

Try:

ILArray<double> A = ILMath.vec<double>(10.0,0.5,15.0);

More array creation functions can be found in the Array section of the documentation. A number of quick reference charts is also available:

ILNumerics' getting started: http://ilnumerics.net/media/oldres/img/ILNumerics_ArraysUsage.pdf

ILNumerics for Matlab users: http://ilnumerics.net/media/oldres/img/ILNumerics4MatlabUsers.pdf

Last but not least the class reference for all ILMath functions: http://ilnumerics.net/apidoc/?topic=html/Methods_T_ILNumerics_ILMath.htm

ILMath function to arrange values given start, end and step size?

1 Answers1