Rails: Using JBuilder views outside of the view context

Question

I am currently switching ActiveModelSeralizer to JBuilder for rendering jsons. I was wondering, with ActiveModelSeralizer I can do something like:

text_content = UserSeralizer.new(user, :root => false)

And receieve the json string in the variable called text_content. Now that I am switching away from ActiveModelSeralizer, is there anyway to do the above with JBuilder?

I have a view partial inside of app/view/api/v1/users/_user.json.jbuilder Is there anyway to render that partial into a variable?

Thanks

Why do you need to assign JSON to a text_content? – Gjaldon Dec 31 '13 at 17:10 — Gjaldon, Dec 31 '13 at 17:10

score 27 · Answer 1 · answered Jan 02 '14 at 14:05

27

Yes, you can. Just use Jbuilder.encode method:

# somewhere in User model

def display_to_json
  Jbuilder.encode do |json|
    json.name name
    json.location display_location
    json.description description
    json.work_experience work_experience
  end
end

and use it:

<!-- somewhere in view, just for example -->
<div ng-init="user = <%= @user.display_to_json %>"></div>

Notice : The class name is Jbuilder, not JBuilder.

answered Jan 02 '14 at 14:05

Tom Chen

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3

This doesn't answer the posted question. It redefines a json representation inside the block and does **not** make use of a present jbuilder template. – Ekkstein Mar 22 '19 at 13:14

score 5 · Answer 2 · answered Feb 04 '16 at 21:22

5

  json = ActionController::Base.new.view_context.render(partial: "api/v1/users/user", locals: {user: @user})

answered Feb 04 '16 at 21:22

Jake

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2

You could also use ```ApplicationController.render(partial: 'my_partial', locals: { my_obj: SomeObj })``` if you want to use helpers inside the partial. – Krzysztof Karski Apr 16 '18 at 11:06
It answers the question albeit being a bit of a long line for a simple task. – Ekkstein Mar 22 '19 at 13:16

score 0 · Answer 3 · answered Jan 02 '14 at 00:59

"I have a view partial inside of app/view/api/v1/users/_user.json.jbuilder Is there anyway to render that partial into a variable?"

How about

json.partial! 'api/v1/users', users: @users.all

This will render the partial and create a new variable, users, with the contents @users.all

score 0 · Answer 4 · answered Jan 04 '14 at 21:40

0

In the Controller I used

render json: whatever

Example:

In items_controller.rb (btw I used MongoDB):

def show
  render json: @item
end

And http://localhost:3000/items/ he replies me with the JSON:

I have not used any views

answered Jan 04 '14 at 21:40

skozz

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score 0 · Answer 5 · edited May 23 '17 at 12:02

0

Try this code:

text_content = json.(user, :id, :name, :published_at)

jbuilder Railscasts

jbuilder response as array

For Render you can use this code:

json.partial! 'api/v1/users', users: @users.all

json render for partial

edited May 23 '17 at 12:02

Community

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answered Jan 04 '14 at 21:40

Mohamed Yakout

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Rails: Using JBuilder views outside of the view context

5 Answers5