How to convert Unix TimeStamp into day:month:date:year format in C?

Question

How do we convert a Unix time stamp in C to day:month:date:year? For eg. if my unix time stamp is 1230728833(int), how we convert this value into this-> Thu Aug 21 2008?

Thanks,

[`man 3 strftime`](http://pubs.opengroup.org/onlinepubs/009695399/functions/strftime.html) — , Sep 02 '13 at 23:42
BTW, the date corresponding to your Unix timestamp is 31 Dec 2008... — , Sep 02 '13 at 23:51

score 9 · Accepted Answer · edited Jan 25 '23 at 18:10

Per @H2CO3's proper suggestion to use strftime(3), here's an example program.

#include <time.h>
#include <stdio.h>
#include <stdlib.h>

static const time_t default_time = 1230728833;
static const char default_format[] = "%a %b %d %Y";

int
main(int argc, char *argv[])
{
        time_t t = default_time;
        const char *format = default_format;

        struct tm lt;
        char res[32];

        if (argc >= 2) {
                t = (time_t) atoi(argv[1]);
        }

        if (argc >= 3) {
                format = argv[2];
        }

        (void) localtime_r(&t, &lt);

        if (strftime(res, sizeof(res), format, &lt) == 0) {
                (void) fprintf(stderr,  "strftime(3): cannot format supplied "
                                        "date/time into buffer of size %u "
                                        "using: '%s'\n",
                                        sizeof(res), format);
                return 1;
        }

        (void) printf("%u -> '%s'\n", (unsigned) t, res);

        return 0;
}

score 2 · Answer 2 · edited Oct 10 '21 at 19:02

This code helps you to convert timestamp from system time into UTC and TAI human readable format.

#include <stdio.h>
#include <time.h>
#include <unistd.h>

int main(void)
{
    time_t     now, now1, now2;
    struct tm  ts;
    char       buf[80];

 
        // Get current time
        time(&now);
        ts = *localtime(&now);
        strftime(buf, sizeof(buf), "%a %Y-%m-%d %H:%M:%S", &ts);
        printf("Local Time %s\n", buf);

        //UTC time
        now2 = now - 19800;  //from local time to UTC time
        ts = *localtime(&now2);
        strftime(buf, sizeof(buf), "%a %Y-%m-%d %H:%M:%S", &ts);
        printf("UTC time %s\n", buf);

        //TAI time valid upto next Leap second added
        now1 = now + 37;    //from local time to TAI time
        ts = *localtime(&now1);
        strftime(buf, sizeof(buf), "%a %Y-%m-%d %H:%M:%S", &ts);
        printf("TAI time %s\n", buf);
        return 0;
}

How to convert Unix TimeStamp into day:month:date:year format in C?

2 Answers2

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