I'm trying to deduce the type of an iterator in a function which is already deducing the argument's type with a template. What I am trying to achieve is substitution for the keyword auto which has similar capability in C++11 standard. Originally I had the following function:
template<typename Type> bool activeExtension(Type &arr)
{
for (auto it=arr.begin(),
ite=arr.end();
it!=ite;
++it)
{
if (*it != 0)
return true;
}
return false;
}
This works perfectly compiling for C++11 standard. But things have changed and I cannot use such features anymore.
I am trying the achieve same functionally without the keyword auto. So I thought about the templates.
So far what I tried is this:
template<typename Type> bool activeExtension(Type &arr)
{
for (Type::iterator it=arr.begin(),
ite=arr.end();
it!=ite;
++it)
{
if (*it != 0)
return true;
}
return false;
}
How would you go to solve this?
Note: I usually call this function with the following type,
template <class T>
struct Generic_t {
typedef std::vector<T> Array;
};
as I have to instantiate a vector with different types.
