What is -ll gcc's flag?

Question

I'm trying to compile a program that there is -ll flag but gcc can't find. What is the l after -lreally a library or is this a typo? is hard find information about this on google.Such term is "vague".

score 8 · Accepted Answer · answered Mar 31 '13 at 17:16

8

-ll means to link against Solaris's libl lex library (available in /usr/lib/libl.so).

(The -l option takes the name of the library, minus the lib prefix and the file extension.)

answered Mar 31 '13 at 17:16

Frédéric Hamidi

258,201
41
486
479

Thanks very much. I can compile without this flag on linux. Can I have some problem in the final executable? – Jack Mar 31 '13 at 17:20
4

If you're on Linux, you are not using the AT&T `lex` but (most likely) `flex` instead. There is a library for `flex` — `libfl.a` or `libfl.so` or similar — and you'd link with it using `-lfl`. However, it provides a dummy `yywrap()` and a dummy `main()`, so you don't normally need it. The `lex` library provides more than that, such as support for `yyreject`, so it is necessary. – Jonathan Leffler Mar 31 '13 at 17:27

score 2 · Answer 2 · answered Mar 17 '19 at 18:31

2

As in my case, flex by default didn't install libfl library (using Linux Mint)

So I had to install libfl-dev library separately

sudo apt install libfl-dev

and include a -lfl option instead of -ll in the commandline as in

gcc myfile.c -lfl -o myfile

answered Mar 17 '19 at 18:31

faruk13

1,276
1
16
23

What is -ll gcc's flag?

2 Answers2