My issue is I have two numbers in the array 5,12 my issue is the code below is returning "1" as true because of the "1" in number 12- it sees the number 1 in 12. How do I tell it to read the ENTIRE number.
<?php
$pos = strpos($foo,"1");
if($pos === false) {
// do this if its false
echo "<img src='../PICS/no.png' width='20' height='20' />";
}
else {
echo "<img src='../PICS/yes.png' width='20' height='20' />";
}
?>
Here's the signature for the function you are using:
int strpos ( string $haystack , mixed $needle [, int $offset = 0 ] )
If you are feeding it with a array as first argument...
<?php
$foo = array(5,12);
$pos = strpos($foo,"1");
... the array will be cast to string and you'll get a notice...
Warning: strpos() expects parameter 1 to be string, array given
The resulting string will contain "Array", literally:
var_dump( @(string)array(5,12) ); // string(5) "Array"
And your search for 1 will always fail because Array does not contain it.
Use in_array()
if (in_array(1,$myarray)){
// found in the array
}
