New to Python, GMail SMTP error

Question

I am writing a simple sendmail function to myself and I keep getting this error:

NameError: name 'SMTPException' is not defined

What is wrong with my code? Any suggestions?

import smtplib

sender = "user@gmail.com"
receiver = ["user@gmail.com"]
message = "Hello!"

try:
    session = smptlib.SMTP('smtp.gmail.com',587)
    session.ehlo()
    session.starttls()
    session.ehlo()
    session.login(sender,'password')
    session.sendmail(sender,receiver,message)
    session.quit()
except SMTPException:
    print('Error')

smptlib -> smtplib – Milovan Tomašević Dec 08 '20 at 06:23 — Milovan Tomašević, Dec 08 '20 at 06:23

score 33 · Accepted Answer · answered Oct 29 '12 at 04:08

33

In Python, you will need to fully qualify the name by prefixing it with its module:

except smtplib.SMTPException:

This is true unless you specifically import the unqualified name (but I wouldn't recommend doing this for your program, just showing what's possible):

from smtplib import SMTPException

answered Oct 29 '12 at 04:08

Greg Hewgill

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5

Not to worry, even after 20 years working with SMTP, I still do that. – Greg Hewgill Oct 29 '12 at 04:12

PascalVKooten · Answer 2 · 2015-06-19T19:33:34.860

That misspelling occurred many times to me as well! One way to circumvent this "problem", is to use yagmail.

Jokes aside, I recently created yagmail to make it easier to send emails.

For example:

import yagmail
yag = yagmail.SMTP('user@gmail.com', 'password')
yag.send(contents = "Hello!")

It uses several shortenings here, for example when To is not defined, it will send a mail to the same email who registered on the server. Also the port and host are the default, which makes it very concise.

In fact, since it seems you want to close the connection immediately, you can even use this one-liner:

yagmail.SMTP('user@gmail.com', 'password').send(contents = "Hello!")

For security, you can keep your password in the keyring (see documentation) such that you do not have to keep your personal password in your scripts, very important! It'll even save you more precious screen-estate.

Going all-in with the package (@gmail.com is default), you can get away with the following:

yagmail.SMTP('user').send('', 'Hello!')

Good luck.

@sureshvv Thanks :) Hope it serves you well. – PascalVKooten Aug 15 '15 at 21:10 — PascalVKooten, Aug 15 '15 at 21:10

score -1 · Answer 3 · answered Jan 24 '23 at 03:47

-1

from smtplib import SMTPExeption

exep smtplib.SMTPExeption

answered Jan 24 '23 at 03:47

Si dingin

1

2

As it’s currently written, your answer is unclear. Please [edit] to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Jan 24 '23 at 15:05

New to Python, GMail SMTP error

3 Answers3

from smtplib import SMTPExeption

Linked