C++ Error in calling the function

Question

I have a function definition of the following form (within a large code):

class Abc{
 public:
 bool func(const std::string& text,::DE::d type,unsigned a,unsigned& b);
 };

Here DE is a class of the following form:

class DE
{
   public:
   enum d{U,L};

};

Now I am calling the function in the following form:

string s;
unsigned st=0;
int idj;
cout<<"\n Enter the value of string:";
cin>>s;
Abc abc;
abc.func(s,DE::U, 0,  idj); 
cout<<idj;

Upon the call of the function func in abc.func(s,DE::U, 0, idj); I am getting the below mentioned error. Can someone be kind enough to help find and rectify the error.

The error that I am getting is:

   error: no matching function for call to ‘Abc::func(std::string&, DE::U, unsigned int&, int&)’

@user1355603, could you, in future, paste **all** of the errors, not single (and not *first*!) error? In many cases, first error gives clues for next of them; you should fix them top-to-bottom, not bottom-to-top. — Griwes, Jun 22 '12 at 09:26

score 4 · Accepted Answer · edited May 23 '17 at 10:09

4

You should read about access specifiers.

class Abc{
 bool func(const std::string& text,::DE::d type,unsigned a,unsigned& b);
};

Abc::func() is private, so cannot be called, or referenced, from outside. Same with enum in DE.

Plus, you cannot pass int, where reference to unsigned int is required.

edited May 23 '17 at 10:09

Community

1
1

answered Jun 22 '12 at 09:22

Griwes

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I am still getting the same error, although the access specifiers are public – user1355603 Jun 22 '12 at 09:24
@user1355603, I added last line after posting this; you want to check it out. – Griwes Jun 22 '12 at 09:25

score 2 · Answer 2 · answered Jun 22 '12 at 09:20

2

idj is of type int; it should be unsigned int to be passed as parameter b.

answered Jun 22 '12 at 09:20

ecatmur

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Mike Seymour · Answer 3 · 2012-06-22T11:30:53.313

2

The last parameter type is a reference to unsigned. You are trying to pass a reference to int, which is a different type.

Once you fix that, you'll find that you can't call the function because it is private; likewise, you can't access DE::U since that's also private. (UPDATE: this refers to the question as originally posted, before public access specifiers were added.)

edited Jun 22 '12 at 11:30

answered Jun 22 '12 at 09:22

Mike Seymour

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C++ Error in calling the function

3 Answers3