can anyone show me an example in java to receive data from DatagramSocket and sending same data through Multicast Socket
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1Please use punctuation signs and write a proper question title! – Alexander Oct 11 '17 at 12:19
2 Answers
Sending multicast datagrams
In order to send any kind of datagram in Java, be it unicast, broadcast or multicast, one needs a java.net.DatagramSocket
:
DatagramSocket socket = new DatagramSocket();
One can optionally supply a local port to the DatagramSocket constructor to which the socket must bind. This is only necessary if one needs other parties to be able to reach us at a specific port. A third constructor takes the local port AND the local IP address to which to bind. This is used (rarely) with multi-homed hosts where it is important on which network adapter the traffic is received.
DatagramSocket socket = new DatagramSocket();
byte[] b = new byte[DGRAM_LENGTH];
DatagramPacket dgram;
dgram = new DatagramPacket(b, b.length,
InetAddress.getByName(MCAST_ADDR), DEST_PORT);
System.err.println("Sending " + b.length + " bytes to " +
dgram.getAddress() + ':' + dgram.getPort());
while(true) {
System.err.print(".");
socket.send(dgram);
Thread.sleep(1000);
}
Receiving multicast datagrams
One can use a normal DatagramSocket to send and receive unicast and broadcast datagrams and to send multicast datagrams. In order to receive multicast datagrams, however, one needs a MulticastSocket. The reason for this is simple, additional work needs to be done to control and receive multicast traffic by all the protocol layers below UDP.
byte[] b = new byte[BUFFER_LENGTH];
DatagramPacket dgram = new DatagramPacket(b, b.length);
MulticastSocket socket =
new MulticastSocket(DEST_PORT); // must bind receive side
socket.joinGroup(InetAddress.getByName(MCAST_ADDR));
while(true) {
socket.receive(dgram); // blocks until a datagram is received
System.err.println("Received " + dgram.getLength() +
" bytes from " + dgram.getAddress());
dgram.setLength(b.length); // must reset length field!
}
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@M-Razavi There is no such thing as a 'broadcast group'. Broadcast and multicast are different things. The question is about multicast, as is this answer. If you have a question of your own, ask it, *as a question*. Otherwise nobody will see it for four years. – user207421 Jul 03 '19 at 11:25
You've got that back to front. You receive multicasts through a MulticastSocket
, but you don't need to send them that way: you can send them via a DatagramSocket
.

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1I am not sure how true the above comment holds. I wasn't able to send multicast packet via a normal DatagramSocket. Only when I started to use a MulticastSocket on the server side, it started showing me the outgoing traffic on sniffing the packets at the server end. – Binita Bharati Feb 08 '16 at 06:10
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@BinitaBharati Anecdotes are not evidence. You need to produce some code. I've been doing what I described here for 20 years. – user207421 Jul 03 '19 at 11:23
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Did not mean to judge your knowledge/expertise. I had faced this in my case, while working on my own project. I do have the project open sourced and on github, but, I do not think, that I would have checked in the offending code to git as well. I should have updated my comment with the non working code, which, I unfortunately did not at that point of time. – Binita Bharati Dec 12 '19 at 10:06