Hibernate, how to count with condition

Question

I am using oracle and hibernate for mapping. I want to count with a condition in count() function. my code is:

select count(case when st.averageMark < su.gradePass then 1 else 0 end)
from Study st join st.subject su
 where st.acaYear in (2009)
  and st.semester = 4
  and su.idSeq = 1330
group by st.acaYear

the code return me nothing. I used sum instead of count it returned a result but it is wrong, the result is bigger than I suppose it to be.

thank in advance.

score 21 · Accepted Answer · edited Feb 15 '18 at 09:38

21

I just solved the problem with the following code.

select sum(case when st.averageMark >= su.gradePass then 1 else 0 end) as pass,
       sum(case when  st.averageMark < su.gradePass then 1 else 0 end) as fail
from Study st join st.subject su
where st.acaYear in (2009) and st.semester = 4 and su.idSeq = 1330
group by st.acaYear

edited Feb 15 '18 at 09:38

Emdadul Sawon

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answered Mar 14 '11 at 07:08

Nathanphan

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1

This is working, case is not supported in count, so sum 1 is count and sum 0 is no count. Thanks – Mr. Mak Mar 13 '17 at 06:16
glass it helps. – Nathanphan Mar 26 '17 at 10:37

score 8 · Answer 2 · edited May 23 '17 at 11:47

8

Combining Nathanphan's answer and M. A. Khomeni's comment,

CASE is not supported in COUNT()

So we need to use SUM() instead of COUNT()

For Example:

COUNT(CASE WHEN st.averageMark < su.gradePass THEN 1 ELSE 0 END)

Should be written as

SUM(CASE WHEN st.averageMark < su.gradePass THEN 1 ELSE 0 END)

edited May 23 '17 at 11:47

Community

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answered May 10 '17 at 12:53

Emdadul Sawon

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Hibernate, how to count with condition

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