Holy CPU cycles batman!
, indeed.
But please rather consider something very fundamental related to numpy
; sophisticated linear algebra based functionality (like random numbers
or singular value decomposition
). Now, consider these seamingly simple calculations:
In []: A= rand(2560000, 3)
In []: %timeit rand(2560000, 3)
1 loops, best of 3: 296 ms per loop
In []: %timeit u, s, v= svd(A, full_matrices= False)
1 loops, best of 3: 571 ms per loop
and please trust me that this kind of performance will not be beaten significantly by any package currently available.
So, please describe your real problem, and I'll try to figure out decent numpy
based solution for it.
Update:
Here is some simply code for ray sphere intersection:
import numpy as np
def mag(X):
# magnitude
return (X** 2).sum(0)** .5
def closest(R, c):
# closest point on ray to center and its distance
P= np.dot(c.T, R)* R
return P, mag(P- c)
def intersect(R, P, h, r):
# intersection of rays and sphere
return P- (h* (2* r- h))** .5* R
# set up
c, r= np.array([10, 10, 10])[:, None], 2. # center, radius
n= 5e5
R= np.random.rand(3, n) # some random rays in first octant
R= R/ mag(R) # normalized to unit length
# find rays which will intersect sphere
P, b= closest(R, c)
wi= b<= r
# and for those which will, find the intersection
X= intersect(R[:, wi], P[:, wi], r- b[wi], r)
Apparently we calculated correctly:
In []: allclose(mag(X- c), r)
Out[]: True
And some timings:
In []: % timeit P, b= closest(R, c)
10 loops, best of 3: 93.4 ms per loop
In []: n/ 0.0934
Out[]: 5353319 #=> more than 5 million detection's of possible intersections/ s
In []: %timeit X= intersect(R[:, wi], P[:, wi], r- b[wi])
10 loops, best of 3: 32.7 ms per loop
In []: X.shape[1]/ 0.0327
Out[]: 874037 #=> almost 1 million actual intersections/ s
These timings are done with very modest machine. With modern machine, a significant speed-up can be still expected.
Anyway, this is only a short demonstration how to code with numpy
.