I have an XML parameter @Xml in SQL Stored procedure like below:
<Root>
<Data>
<Id>1</Id>
<Name>Kevin</Name>
<Des>Des1</Des>
</Data>
<Data>
<Id>2</Id>
<Name>Alex</Name>
<Des>Des2</Des>
</Data>
<Data>
<Id>3</Id>
<Name>Amy</Name>
<Des>Des3</Des>
</Data>
</Root>
now, I want to delete several nodes in this xml, the filter is like this (Id = 2 AND Name = 'Alex') OR (Id = 3 AND Name = 'Amy'), I don't want to use Cursor or something like this, just using one single script to do it, I am try to my best for this, but I can't get the answer, anybody can help me ? Thanks in advance!!!
The output should be :
<Root>
<Data>
<Id>1</Id>
<Name>Kevin</Name>
<Des>Des1</Des>
</Data>
</Root>
PS: the filter is a #table, so, the actually question is , how to remove the specific records in XML which contains in #table?
Id Name
2 Alex
3 Amy
Declare @Xml XML
set @Xml = '<Root>
<Data>
<Id>1</Id>
<Name>Kevin</Name>
<Des>Des1</Des>
</Data>
<Data>
<Id>2</Id>
<Name>Alex</Name>
<Des>Des2</Des>
</Data>
<Data>
<Id>3</Id>
<Name>Amy</Name>
<Des>Des3</Des>
</Data>
</Root>'
create TABLE #tempResult
(
Id Int,
Name Varchar(10)
)
insert into #tempResult
values(2, 'Alex'), (3, 'Amy')
SET @Xml = (
SELECT Node.value('Id[1]','int') AS PId, Node.value('Name[1]','Varchar(10)') AS PName
FROM @Xml.nodes('//Data') AS T(Node)
OUTER APPLY (
SELECT tr.Id, tr.Name
FROM #tempResult tr
WHERE Node.value('Id[1]','int') = tr.Id and Node.value('Name[1]','Varchar(10)') = tr.Name
) a
WHERE a.Id IS NULL
FOR XML PATH(''), TYPE
)
select @Xml
drop table #tempResult
I got results like this 1 Kevin
But I need the the whole xml contains Root node:
<Root>
<Data>
<Id>1</Id>
<Name>Kevin</Name>
<Des>Des1</Des>
</Data>
</Root>
How can I reach this? Any help? I am an new leaner for SQL to XML, please help me !!!