TypeError: 'range' object does not support item assignment

Question

I was looking at some python 2.x code and attempted to translate it to py 3.x but I'm stuck on this section. Could anyone clarify what is wrong?

import random

emails = {
    "x": "[REDACTED]@hotmail.com",
    "x2": "[REDACTED]@hotmail.com",
    "x3": "[REDACTED]@hotmail.com"
}

people = emails.keys()

#generate a number for everyone
allocations = range(len(people))
random.shuffle(allocations)

This was the error given:

TypeError: 'range' object does not support item assignment

score 107 · Accepted Answer · edited Aug 21 '18 at 00:01

107

In Python 3, range returns a lazy sequence object - it does not return a list. There is no way to rearrange elements in a range object, so it cannot be shuffled.

Convert it to a list before shuffling.

allocations = list(range(len(people)))

edited Aug 21 '18 at 00:01

user2357112

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answered Dec 10 '13 at 01:14

Tim

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Do you happen to know the equivalent of xrange for python3? – user2840982 Dec 10 '13 at 01:16
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Python3's `range` is identical to python2's `xrange`. The old `range` no longer exists. – Tim Dec 10 '13 at 01:17
it returns a range object which is a sequence type – user391339 Sep 07 '20 at 00:34

score 0 · Answer 2 · edited Feb 09 '21 at 11:03

0

if you can use numpy library you can replace range with np.arange:

import numpy as np
allocations = np.arange(len(people))

edited Feb 09 '21 at 11:03

sigma1510

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answered Feb 09 '21 at 10:42

Ehsan Rajabi

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It's way overkill to import `numpy` for this, when it can be done natively just by using `list()`. – pfabri Feb 09 '21 at 11:21

TypeError: 'range' object does not support item assignment

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