Solving exponential equations using logarithms: base-2

We can use logarithms to solve *any* exponential equation of the form a⋅bᶜˣ=d. For example, this is how you can solve 3⋅10²ˣ=7: 1\. Divide by 3: 10²ˣ=7/3 2\. Use the definition of logarithm: 2x=log(7/3) 3\. Divide by 2: x=log(7/3)/2 Now you can use a calculator to find the solution of the equation as a rounded decimal number ​

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